NCERT Solutions Class 6 Maths Chapter 3 Playing With Numbers Exercise 3.1 are provided here. These solutions are prepared by expert teachers to guide you in your exam preparation. The solutions are always prepared by following NCERT guidelines, so that it covers the whole syllabus accordingly. Our CBSE Class 6 Maths Solutions Chapter 3 Exercise 3.1 Solutions are very helpful in scoring well in examinations.
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Exercise 3.1
EXERCISE 3.1
Question 1: Write all the factors of the following numbers:
(a) 24
(b) 15
(c) 21
(d) 27
(e) 12
(f) 20
(g) 18
(h) 23
(i) 36
Solution:
(a) 24
24 = 1 × 24
24 = 2 × 12
24 = 3 × 8
24 = 4 × 6
24 = 6 × 4
Stop here since 4 and 6 have occurred earlier
Hence, the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24
(b) 15
15 = 1 × 15
15 = 3 × 5
15 = 5 × 3
Stop here since 3 and 5 have occurred earlier
Hence, the factors of 15 are 1, 3, 5 and 15
(c) 21
21 = 1 × 21
21 = 3 × 7
21 = 7 × 3
Stop here since 3 and 7 have occurred earlier
Hence, the factors of 21 are 1, 3, 7 and 21
(d) 27
27 = 1 × 27
27 = 3 × 9
27 = 9 × 3
Stop here since 3 and 9 have occurred earlier
Hence, the factors of 27 are 1, 3, 9 and 27
(e) 12
12 = 1 × 12
12 = 2 × 6
12 = 3 × 4
12 = 4 × 3
Stop here since 3 and 4 have occurred earlier
Hence, the factors of 12 are 1, 2, 3, 4, 6 and 12
(f) 20
20 = 1 × 20
20 = 2 × 10
20 = 4 × 5
20 = 5 × 4
Stop here since 4 and 5 have occurred earlier
Hence, the factors of 20 are 1, 2, 4, 5 10 and 20
(g) 18
18 = 1 × 18
18 = 2 × 9
18 = 3 × 6
18 = 6 × 3
Stop here since 3 and 6 have occurred earlier
Hence, the factors of 18 are 1, 2, 3, 6, 9 and 18
(h) 23
23 = 1 × 23
23 = 23 × 1
Since 1 and 23 have occurred earlier
Hence, the factors of 23 are 1 and 23
(i) 36
36 = 1 × 36
36 = 2 × 18
36 = 3 × 12
36 = 4 × 9
36 = 6 × 6
Stop here, since both the factors (6) are same.
Thus, the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18 and 36
Question 2: Write first five multiples of:
(a) 5
(b) 8
(c) 9
Solution:
(a) The required multiples are:
5 × 1 = 5
5 × 2 = 10
5 × 3 = 15
5 × 4 = 20
5 × 5 = 25
Hence, the first five multiples of 5 are 5, 10, 15, 20 and 25
(b) The required multiples are:
8 × 1 = 8
8 × 2 = 16
8 × 3 = 24
8 × 4 = 32
8 × 5 = 40
Hence, the first five multiples of 8 are 8, 16, 24, 32 and 40
(c) The required multiples are:
9 × 1 = 9
9 × 2 = 18
9 × 3 = 27
9 × 4 = 36
9 × 5 = 45
Hence, the first five multiples of 9 are 9, 18, 27, 36 and 45
Question 3: Match the items in column 1 with the items in column 2.
Column 1 Column 2
(i) 35 (a) Multiple of 8
(ii) 15 (b) Multiple of 7
(iii) 16 (c) Multiple of 70
(iv) 20 (d) Factor of 30
(v) 25 (e) Factor of 50
(f) Factor of 20
Solution:
(i) ↔ (b) [∵ 7 × 5 = 35]
(ii) ↔ (d) [∵ 15 × 2 = 30]
(iii) ↔ (a) [∵ 8 × 2 = 16]
(iv) ↔ (f) [∵ 20 × 1 = 20]
(v) ↔ (e) [∵ 25 × 2 = 50]
Question 4: Find all the multiples of 9 up to 100.
Solution:
9 × 1 = 9
9 × 2 = 18
9 × 3 = 27
9 × 4 = 36
9 × 5 = 45
9 × 6 = 54
9 × 7 = 63
9 × 8 = 72
9 × 9 = 81
9 × 10 = 90
9 × 11 = 99
∴ All the multiples of 9 up to 100 are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99
Access NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers – All Exercises
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